Switched the question again, by simplifying. I figure, if you're actually executing all the instructions of DMSI successfully and permanently, then you've also bypassed/overcome any resistance.
So...
"How many loops is best for me, when I next run DMSI, for actually, successfully, and permanently executing all of the instructions that make up DMSI 3.1-()." (In my case, DMSI 3.1[A])
Answer: 5 loops
Second best: 1 loop
Interesting.
Yesterday mid-morning was my last day of 1 loop. Rather than waiting over 24 hours, I went ahead an ran 5 loops overnight - a mixture of hybrid and masked. 2 hybrid, 3 masked.
EDIT: Going to change this question again today to add "...as successfully, quickly, and consistently as possible." after "...that make up DMSI 3.1()" Though I wonder if using "successfully" here again is redundant.
So...
"How many loops is best for me, when I next run DMSI, for actually, successfully, and permanently executing all of the instructions that make up DMSI 3.1-()." (In my case, DMSI 3.1[A])
Answer: 5 loops
Second best: 1 loop
Interesting.
Yesterday mid-morning was my last day of 1 loop. Rather than waiting over 24 hours, I went ahead an ran 5 loops overnight - a mixture of hybrid and masked. 2 hybrid, 3 masked.
EDIT: Going to change this question again today to add "...as successfully, quickly, and consistently as possible." after "...that make up DMSI 3.1()" Though I wonder if using "successfully" here again is redundant.
