just wondering about bluetooth

[hiddenalias]

Okay but keep it at an appropriate volume will be good even for a cell phone that produces static on high volume. Is that basically what you are getting at? Because that is how I am understanding what you are saying that using anything that produces static is okay when played at a appropriate volume without over maxing it.

If the volume is properly calibrated and there is still static, there is a problem either with the file (possible corruption on transfer), the player app, or the hardware itself. If other files play fine in the same app on the same device, then rule out a bad file transfer first, then if there's still static even with good headphones plugged in assume the device is not capable of outputting the high frequencies advertised.

So! Once again, the order is: check the volume first and confirm it is or isn't the volume, then check the app with other files and confirm it is or isn't the app, then re-transfer the sub and confirm you moved it ok, then try with headphones guaranteed to have worked to confirm it is or isn't the phone's speakers vs. the headphone jack, THEN through process of elimination the problem will be revealed as the phone not outputting the necessary high frequencies.

Thanks for breaking it down; I know it doesn't take a rocket scientist or einstein to figure it out but I just felt contradicted when Shannon talks about stereo systems that can handle 20 khz are the only units that should be used and then you (the way I felt) made it sound like it doesn't have to have 20 khz capability as long as you can keep it at comfortable hearing volume where you don't hear static it will be just as good.

Other than that at least this will help anybody in the future who has the same question to come look at this post to give them their answer (probably wasn't asked before so I guess I did some service to post a question like this becuz I bet you it will come up again with any new members coming to find answers about this and at least it will be here).