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+--- Thread: Technical Question regarding FLAC (/Thread-Technical-Question-regarding-FLAC)
Technical Question regarding FLAC - Blacksheep - 12-21-2016
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RE: Technical Question regarding FLAC - apollolux - 12-21-2016
It's probably the conversion from megabytes (marketing speak) to binary megabytes/mebibytes (actual measure); 549 megabytes = 549*1'000'000 = 549'000'000 bytes, 549'000'000/(1024*1024) = 523.567 mebibytes.
RE: Technical Question regarding FLAC - Blacksheep - 12-22-2016
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